penyerhanaan bentuk akar. dari. 108
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Jawaban:
[tex] \sqrt{108} \\ = \sqrt{ {6}^{2} } \times 3 \\ = \sqrt(6 \times 6) \times 3 \\ = \sqrt{36 \times 3} \\ = 3\sqrt{6} \\ = 6\sqrt{3} [/tex]
Semoga membantu
#Swmwngat
#Ciss ♡♡
Penyelesaian:
[tex] \large \sf \sqrt{108} [/tex]
[tex] \large \sf = \sqrt{36.3} [/tex]
[tex] \large \sf = \sqrt{ {6}^{2} .3} [/tex]
[tex] \large \sf = \boxed{\red{ \bf6\sqrt{3} }}[/tex]
Semoga membantu.
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